Basic Authentication

[Cyberizm]

Objective-C:​

Vulnerable Code:

- (void)connection:(NSURLConnection *)connection willSendRequestForAuthenticationChallenge:(NSURLAuthenticationChallenge *)challenge {
    NSString *user = @"user";
    NSString *pass = @"pass";
    if ([[challenge protectionSpace] receivesCredentialSecurely] == YES && [[[challenge protectionSpace] host] isEqualToString:@"myhost.com"]) {
        NSURLCredential *credential = [NSURLCredential credentialWithUser:user password:pass persistence:NSURLCredentialPersistenceForSession];
        [[challenge sender] useCredential:credential forAuthenticationChallenge:challenge];
    }
}
Description: This vulnerable code implements HTTP basic authentication using NSURLConnection. However, it hardcodes the username and password directly in the code, which poses a security risk.

Patched Code:

- (void)connection:(NSURLConnection *)connection willSendRequestForAuthenticationChallenge:(NSURLAuthenticationChallenge *)challenge {
    NSURLCredential *credential = [self retrieveCredentialFromKeychainForChallenge:challenge];
    if (credential) {
        [[challenge sender] useCredential:credential forAuthenticationChallenge:challenge];
    } else {
        // Handle authentication failure or prompt user for credentials
    }
}

- (NSURLCredential *)retrieveCredentialFromKeychainForChallenge:(NSURLAuthenticationChallenge *)challenge {
    // Retrieve stored credentials from Keychain based on protection space
    // Implement this method to securely fetch credentials from Keychain
    // Return NSURLCredential object or nil if not found
}
Description: The patched code retrieves the username and password from the Keychain instead of hardcoding them, enhancing security. It delegates the responsibility of securely fetching credentials from the Keychain to a separate method, reducing the risk of exposing sensitive information.

Swift:

Vulnerable Code:

func connection(_ connection: NSURLConnection, willSendRequestFor challenge: URLAuthenticationChallenge) {
    let user = "user"
    let pass = "pass"
    if challenge.protectionSpace.receivesCredentialSecurely == true && challenge.protectionSpace.host == "myhost.com" {
        let credential = URLCredential(user: user, password: pass, persistence: .forSession)
        challenge.sender?.use(credential, for: challenge)
    }
}
Description: Similar to the Objective-C code, this vulnerable Swift code implements HTTP basic authentication with hardcoded credentials, posing a security risk.

Patched Code:

func connection(_ connection: NSURLConnection, willSendRequestFor challenge: URLAuthenticationChallenge) {
    guard let credential = retrieveCredentialFromKeychain(for: challenge) else {
        // Handle authentication failure or prompt user for credentials
        return
    }
    challenge.sender?.use(credential, for: challenge)
}

func retrieveCredentialFromKeychain(for challenge: URLAuthenticationChallenge) -> URLCredential? {
    // Retrieve stored credentials from Keychain based on protection space
    // Implement this method to securely fetch credentials from Keychain
    // Return URLCredential object or nil if not found
}

Description: The patched Swift code also retrieves credentials from the Keychain instead of hardcoding them, improving security. It separates the credential retrieval logic into a dedicated method, promoting code readability and maintainability.





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